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Motion in a straight line Grade 10 Science lesson 02 Quiz 01

O/LScienceMotion in a straight lineEnglishEasy20 questions

Free G.C.E. O/L Science MCQ quiz on Motion in a straight line with 20 questions in English medium. Answer each question, see the correct answer and explanation straight away, and get your score at the end. Use the study section below to review every question and answer.

සාමාන්‍ය පෙළ Science බහුවරණ ප්‍රශ්න නොමිලේ පුහුණු වන්න.

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About this quiz

Master Motion in a Straight Line: Free Online Quiz & MCQ Practice for Grade 10 Science (Lesson 02)Strengthen your understanding of physics fundamentals with this free, interactive online quiz on Motion in a Straight Line (Grade 10 Science, Unit 02). Whether you are revising for unit tests, term exams, or national syllabus assessments, this practice test is designed to sharpen your problem-solving skills, clarify conceptual doubts, and boost your exam confidence.Linear motion is one of the most heavily tested physics topics in secondary school science. This quiz breaks down standard multiple-choice questions (MCQs), covering everything from scalar and vector quantities to motion graph interpretations and equations of motion.Key Topics Covered in This Quiz:Distance vs. Displacement: Differentiating between scalar and vector measurements, reference points, and direction.Speed and Velocity: Calculating uniform speed, average speed, instantaneous velocity, and unit conversions ($m/s$, $km/h$).Acceleration & Deceleration: Understanding positive acceleration, uniform acceleration, and retardation with real-world scenarios.Displacement-Time ($s-t$) Graphs: Reading gradients to find velocity, identifying stationary states, and interpreting uniform motion.Velocity-Time ($v-t$) Graphs: Calculating acceleration from slopes and finding total displacement/distance from the area under the graph.Linear Motion Equations: Solving standard kinematics problems using $v = u + at$, s = ut + 1/2at2, and v2 = u2 + 2as.Key Features & Benefits:Instant Grading & Step-by-Step Solutions: Get your score immediately along with answer keys to learn from your mistakes on the spot.Curriculum-Aligned Questions: Structured according to national and international secondary school science syllabi to reflect real exam question styles.Timed or Untimed Practice: Build mental calculation speed and analytical reasoning under exam conditions.100% Free & Device Friendly: Practice on your mobile, tablet, or PC without mandatory subscriptions or hidden paywalls.Who Should Take This Test?Grade 10 Science students preparing for Lesson 02 classroom assessments and term tests.O/L candidates revising foundational physics modules.Teachers and tutors looking for a digital formative assessment tool for their students.

All questions & answers (20)

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  1. Q1. A physical quantity that can be described only by its magnitude is called a:

    • A)Vector quantity
    • B)Scalar quantity
    • C)Derived quantity
    • D)Fundamental quantity
    Show answer & explanation

    Answer: B) Scalar quantity

    A scalar quantity is fully described by its magnitude alone, without any direction.

  2. Q2. Which of the following is classified as a vector quantity?

    • A)Distance
    • B)Speed
    • C)Time
    • D)Displacement
    Show answer & explanation

    Answer: D) Displacement

    Displacement has both magnitude and direction, making it a vector quantity.

  3. Q3. What is the standard SI unit of acceleration?

    • A)m s−1
    • B)m s−2
    • C)m2 s−1
    • D)kg m s−2
    Show answer & explanation

    Answer: B) m s−2

    Since acceleration is the rate of change of velocity (velocity change per unit time), its unit is meters per second squared (m s−2).

  4. Q4. The rate of change of distance or the distance traversed in a unit time is known as:

    • A)Velocity
    • B)Acceleration
    • C)Speed
    • D)Displacement
    Show answer & explanation

    Answer: C) Speed

    Speed is defined as the rate at which a given distance is traversed (speed = distance / time).

  5. Q5. The rate of change of displacement is defined as:

    • A)Speed
    • B)Velocity
    • C)Acceleration
    • D)Momentum
    Show answer & explanation

    Answer: B) Velocity

    Velocity is the rate of change of displacement, making it a vector quantity.

  6. Q6. A negative acceleration is commonly known as:

    • A)Uniform speed
    • B)Free fall
    • C)Deceleration
    • D)Instantaneous velocity
    Show answer & explanation

    Answer: C) Deceleration

    A decrease in velocity over time results in a negative acceleration, which is called deceleration or retardation.

  7. Q7. What does the gradient of a displacement-time graph represent?

    • A)Acceleration
    • B)Distance
    • C)Velocity
    • D)Deceleration
    Show answer & explanation

    Answer: C) Velocity

    The gradient of a displacement-time graph is calculated by dividing displacement by time, which gives the velocity.

  8. Q8. What does the gradient of a velocity-time graph represent?

    • A)Displacement
    • B)Speed
    • C)Acceleration
    • D)Total distance
    Show answer & explanation

    Answer: C) Acceleration

    The gradient of a velocity-time graph represents the velocity change divided by time, which is acceleration.

  9. Q9. What does the area under a velocity-time graph represent?

    • A)Acceleration
    • B)Displacement
    • C)Instantaneous speed
    • D)Average force
    Show answer & explanation

    Answer: B) Displacement

    Multiplying velocity (y-axis) by time (x-axis) gives the displacement represented by the area under a velocity-time graph.

  10. Q10. The average value for the gravitational acceleration (g) near the Earth's surface is approximately:

    • A)4.9 m s−2
    • B)9.8 m s−2
    • C)10.5 m s−2
    • D)1.6 m s−2
    Show answer & explanation

    Answer: B) 9.8 m s−2

    The average value for gravitational acceleration at sea level is about 9.8 m s−2.

  11. Q11. A child walks 40 m to the East and then 30 m to the North. What is the magnitude of his total displacement from the starting point?

    • A)70 m
    • B)50 m
    • C)10 m
    • D)1200 m
    Show answer & explanation

    Answer: B) 50 m

    Using Pythagoras' theorem for a right-angled triangle, displacement = sqrt(40^2 + 30^2) = sqrt(1600 + 900) = sqrt(2500) = 50 m.

  12. Q12. In question 11, what is the total distance traversed by the child?

    • A)50 m
    • B)10 m
    • C)70 m
    • D)35 m
    Show answer & explanation

    Answer: C) 70 m

    Total distance is the sum of path lengths: 40 m + 30 m = 70 m.

  13. Q13. An object travels a total distance of 18 m in a total time of 6 s. What is its mean speed?

    • A)2 m s−1
    • B)3 m s−1
    • C)6 m s−1
    • D)18 m s−1
    Show answer & explanation

    Answer: B) 3 m s−1

    Mean speed = total distance / total time = 18 m / 6 s = 3 m s−1.

  14. Q14. If a body moves at a constant velocity of 6 m s−1 for 5 s, what is its displacement?

    • A)1.2 m
    • B)11 m
    • C)30 m
    • D)3 m
    Show answer & explanation

    Answer: C) 30 m

    Displacement = velocity × time = 6 m s−1 × 5 s = 30 m.

  15. Q15. An object's velocity increases uniformly from 0 to 12 m s−1 in 6 s. What is its acceleration?

    • A)1 m s−2
    • B)2 m s−2
    • C)3 m s−2
    • D)6 m s−2
    Show answer & explanation

    Answer: B) 2 m s−2

    Acceleration = (final velocity - initial velocity) / time = (12 - 0) / 6 = 2 m s−2.

  16. Q16. If an object's velocity decreases uniformly from 16 m s−1 to 4 m s−1 in 4 s, what is its deceleration?

    • A)3 m s−2
    • B)4 m s−2
    • C)12 m s−2
    • D)5 m s−2
    Show answer & explanation

    Answer: A) 3 m s−2

    Acceleration = (4 - 16) / 4 = -12 / 4 = -3 m s−2. Therefore, the deceleration is 3 m s−2.

  17. Q17. A body starting from rest accelerates at 0.5 m s−2 for 10 s. What is its final velocity?

    • A)2 m s−1
    • B)5 m s−1
    • C)10 m s−1
    • D)20 m s−1
    Show answer & explanation

    Answer: B) 5 m s−1

    Velocity = initial velocity + (acceleration × time) = 0 + (0.5 × 10) = 5 m s−1.

  18. Q18. A body starting from rest is subjected to a uniform acceleration for 6 s, acquiring a velocity of 12 m s−1. What is its displacement during this time?

    • A)18 m
    • B)36 m
    • C)72 m
    • D)6 m
    Show answer & explanation

    Answer: B) 36 m

    Displacement = mean velocity × time = [(0 + 12) / 2] × 6 = 6 × 6 = 36 m.

  19. Q19. A fruit falling freely from a tree takes 4 s to reach the ground. What is its velocity upon impact (taking g = 9.8 m s−2)?

    • A)9.8 m s−1
    • B)19.6 m s−1
    • C)39.2 m s−1
    • D)78.4 m s−1
    Show answer & explanation

    Answer: C) 39.2 m s−1

    Velocity = g × t = 9.8 m s−2 × 4 s = 39.2 m s−1.

  20. Q20. Using the values from question 19, what is the height from which the fruit fell?

    • A)39.2 m
    • B)78.4 m
    • C)19.6 m
    • D)156.8 m
    Show answer & explanation

    Answer: B) 78.4 m

    Height (displacement) = mean velocity × time = [(0 + 39.2) / 2] × 4 = 19.6 × 4 = 78.4 m.

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